Waec Mathematics 1993 Past Questions and Answers

Question 1:

• WAEC 1993

S = {1, 2, 3, 4, 5, 6}, T = {2,4,5,7} and R = {1,4, 5}, and (S∩T) ∪ R

A. {1, 4, 5}
B. {2, 4, 5}
C. {1, 2, 4, 5}
D. {2, 3, 4, 5}
E. {1, 2, 3, 4, 5}

Question 2:

• WAEC 1993

S = {1, 2, 3, 4, 5, 6}, T = {2,4,5,7} and R = {1,4, 5}, and (S∩T) ∪ R

A. {1, 4, 5}
B. {2, 4, 5}
C. {1, 2, 4, 5}
D. {2, 3, 4, 5}
E. {1, 2, 3, 4, 5}

Question 3:

• WAEC 1993

Simplify: \(\frac{3}{4} \div 1\frac{1}{4} \times (1\frac{1}{2} - \frac{2}{3})\)

A. 7/30
B. 7/24
C. 9/25
D. ¹/₂
E. 18/25

Question 4:

• WAEC 1993

Solve the inequality: 3m + 3 > 9

A. M > 2
B. M > 3
C. M>4
D. M>6
E. M>12

Question 5:

• WAEC 1993

Convert 89\(_{10}\) to a number in base two.

A. 1101001
B. 1011001
C. 1001101
D. 101101
E. 11001