Waec Further Mathematics Past Questions and Answers

Question 461:

• WAEC 2011

Simplify \(\sqrt[3]{\frac{8}{27}} - (\frac{4}{9})^{-\frac{1}{2}}\)

A. \(\frac{-5}{6}\)
B. \(-\frac{4}{27}\)
C. \(0\)
D. \(\frac{2}{9}\)

Question 462:

• WAEC 2011

Solve \(3x^{2} + 4x + 1 > 0\)

A. \(x < -1, x < -\frac{1}{3}\)
B. \(x > -1, x > -\frac{1}{3}\)
C. \(x > \frac{1}{3}, x < -1\)
D. \(x < \frac{1}{3}, x > -1\)

Question 463:

• WAEC 2011

The equation of a circle is \(3x^{2} + 3y^{2} + 6x - 12y + 6 = 0\). Find its radius

A. 1
B. \(\sqrt{3}\)
C. \(\sqrt{11}\)
D. \(\sqrt{6}\)

Question 464:

• WAEC 2011

\(f(x) = p + qx\), where p and q are constants. If f(1) = 7 and f(5) = 19, find f(3).

A. 13
B. 15
C. 17
D. 26

Question 465:

• WAEC 2011

The sum and product of the roots of a quadratic equation are \(\frac{4}{7}\) and \(\frac{5}{7}\) respectively. Find its equation.

A. \(7x^{2} - 4x - 5 = 0\)
B. \(7x^{2} - 4x + 5 = 0\)
C. \(7x^{2} + 4x - 5 = 0\)
D. \(7x^{2} + 4x + 5 = 0\)