Further Mathematics 2020 Waec Past Questions and Answers

Question 36 :

• WAEC 2020

Simplify; \(\frac{\sqrt{5} + 3}{4 - \sqrt{10}}\)

A. \(\frac{2}{3}\)\(\sqrt{5}\) + \(\frac{5}{6}\sqrt{2}\) + 2
B. \(\frac{2}{3}\)\(\sqrt{5}\) + \(\frac{5}{6}\sqrt{2}\) + \(\frac{1}{2}\sqrt{10}\)
C. \(\frac{2}{3}\)\(\sqrt{5}\) + \(\frac{5}{6}\sqrt{2}\) + \(\frac{1}{2}\sqrt{10}\) + 2
D. \(\frac{2}{3}\)\(\sqrt{5}\) - \(\frac{5}{6}\sqrt{2}\) + \(\frac{1}{2}\sqrt{10}\) + 2

Question 37 :

• WAEC 2020

If \(\frac{6x + k}{2x^2 + 7x - 15}\) = \(\frac{4}{x + 5} - \frac{2}{2x - 3}\). Find the value of k.

A. - 21
B. - 22
C. - 24
D. - 25

Question 38 :

• WAEC 2020

Differentiate \(\frac{x}{x + 1}\) with respect to x.

A. \(\frac{x}{x + 1}\)
B. \(\frac{-1}{x + 1}\)
C. \(\frac{1 - x}{(x + 1)^2}\)
D. \(\frac{1}{(x + 1)^2}\)

Question 39 :

• WAEC 2020

Given that 2x + 3y - 10 and 3x = 2y - 11, calculate the value of (x - y).

A. 5
B. 3
C. - 3
D. - 5

Question 40 :

• WAEC 2020

Given that X : R \(\to\) R is defined by x = \(\frac{y + 1}{5 - y}\) , y \(\in\) R, find the domain of x.

A. {y : y \(\in\) R, y \(\neq\) 0}
B. {y : y \(\in\) R, y \(\neq\) 1}
C. {y : y \(\in\) R, y \(\neq\) 5}
D. {y : y \(\in\) R, y \(\neq\) 7}