Further Mathematics 2015 Waec Past Questions and Answers

Question 11 :

• WAEC 2015

If \(\begin{vmatrix} 1+2x & -1 \\ 6 & 3-x \end{vmatrix} = -3 \), find the values of x.

A. \(x = 3, -2\)
B. \(x = 4, \frac{-2}{3}\)
C. \(x = -4, \frac{3}{2}\)
D. \(x = 4, \frac{-3}{2}\)

Question 12 :

• WAEC 2015

Find \(\int \frac{x^{3} + 5x + 1}{x^{3}} \mathrm {d} x\)

A. \(x^{2} + 10x + c\)
B. \(x + \frac{5}{3}x^{3} + x^{4} + c\)
C. \(x - 5x^{2} - 2x^{3} + c\)
D. \(x - \frac{5}{x} - \frac{1}{2x^{2}} + c\)

Question 13 :

• WAEC 2015

Find the coordinates of the point which divides the line joining P(-2, 3) and Q(4, 6) internally in the ratio 2 : 3.

A. \((5\frac{2}{5}, \frac{2}{5})\)
B. \((\frac{2}{5}, 5\frac{2}{5})\)
C. \((\frac{-2}{5}, 5\frac{2}{5})\)
D. \((\frac{2}{5}, 4\frac{1}{5})\)

Question 14 :

• WAEC 2015

A particle starts from rest and moves in a straight line such that its acceleration after t seconds is given by \(a = (3t - 2) ms^{-2}\). Find the other time when the velocity would be zero.

A. \(\frac{1}{3} seconds\)
B. \(\frac{3}{4} seconds\)
C. \(\frac{4}{3} seconds\)
D. \(2 seconds\)

Question 15 :

• WAEC 2015

A particle starts from rest and moves in a straight line such that its acceleration after t secs is given by \(a = (3t - 2) ms^{-2}\). Find the distance covered after 3 secs.

A. \(10m\)
B. \(9m\)
C. \(\frac{13}{3} m\)
D. \(\frac{9}{2} m\)