Given: \(V_{0}=10^{-6} m ^{3}, T_{1}=273 K , T_{2}=573 K\), \(\alpha=1.2 \times 10^{-5}\) \(3 \alpha=\frac{\Delta V}{V_{0} \Delta_{\theta}} ; \frac{\Delta V}{V_{0}}=3 \alpha \times \Delta \theta\) \(=3 \times 1.2 \times 10^{-5} \times(573-273)=0.0108\) \(\frac{\Delta V}{V_{o}} \times 100 \%=1.1 \%\)