The electric field between two parallel plates is E. A particle of mass \(m\) and carrying charge \(q\) is released at a point half the distance between the plates. The velocity of the particle \(t\) seconds after its release is ____________
A. \(q E t / m\) B. \(q E R / 2 m\) C. \(m q R / 2 E\) D. \(m q t / 2 E\)
Correct Answer: A
Explanation
Given data: \(M=\) mass, \(q=\) charge, electric field strength \(=E\) required velocity \(=\) ?rom \(E=\frac{\text { force }}{\text { Charge }}\), force \(=E q\)lso \(f=m a\) and \(a= v / t\) So that \(f=E q=\frac{m v}{t}\) and \(V=\frac{E q t}{m}\).
