Heat required to melt the ice completely at \(0^{\circ} C +\) heat absorbed by the container + heat required to raise the temperature of water and the container heat delivered i.e.
\(M l_{ f }+ M _{ rec } C _{ ice } \Delta \theta+ M _{ c } C _{ c } \Delta \theta\)
\(=\) heat delivered
\(C _{\text {ice }}=\) S.H.C of ice,
Mice \(=\) mass of ice \(=0.01 kg\)
\(I_{f}=\) S.L H of ice
also \(M _{c} \Delta \theta= C \Delta \theta=20 \times \Delta \theta\),
we substitute these values
\(600=0.01 \times 3.33 \times 10^{5}+0.01 \times 4200 \times(\theta-0)+20(\theta-0)\)
\(6000=3330+42 \theta+20 \theta\)
\(2670=62 \theta, \theta=43.06^{\circ} C \approx 43^{\circ} C\)