A coin is at the bottom of a bucket filled with a liquid whose refractive index is \(1.35\). The coin appears to be \(12.0 cm\) below the surface of the liquid. Calculate the depth of the liquid.
A. \(16.2 cm\) B. \(13.4 cm\) C. \(8.9 cm\) D. \(5.4 cm\)
Correct Answer: A
Explanation
Refractive index \(n =1.35\),pparent depth \(=12 cm\) $$ \begin{aligned} n &=\frac{\text { Real depth }}{\text { Apparant depth }}=1.35 \\25 &=\frac{\text { Real depth }}{12 cm }, \\ \text { Real depth } &=1.35 \times 12 cm \\ &=16.2 cm \end{aligned} $$
