The force on current carrying conductor in a masnetic field is least when the
A. conductor makes an angle of \(100^{\circ}\) with the field B. force is independent of the angle between the conductor and the field C. conductor is parallel with the field D. conductor is at right angle with the field
Correct Answer: C
Explanation
conductor at right angle with the field.orce on a current carrying conductor is given by \(f=\) Bilsin \(\theta\) \(B =\) strength of the field \(i=\) magnitude of the current \(l=\) length of the conductor \(\theta =\) angle which the conductor makes with the field if \(\theta=90^{\circ}\) then \(F=\) Bil \(\sin 90^{\circ}(\sin 90=1)\) \(F=\operatorname{Bil}(\max\) force) and if \(\theta=0\) i.e. when conductor is parallel to the field, \(F=B i l \sin 0(\sin 0=0)\) \(F=B i l \times 0=0\) It will experience least or no force if \(\theta=0\)