Normal weight of the metal \(=(3.6 \times 10) N =36 N\)
$$
\begin{gathered}
\text { Volume }(V) \text { of metal }=\frac{\text { mass }}{\text { density }} \\
=\left(\frac{3.6}{9000}\right) m ^{3} .
\end{gathered}
$$
Upthrust \(=\rho V g\)
$$
=1000 \times \frac{3.6}{9000} \times 10=4 N
$$
Reading of the spring balance when immersed in water (apparent weight in water) \(=36 N -4 N =32 N\)