\begin{aligned}
P_{\text {heater }} &=\frac{V^{2}}{R}, R=\frac{V^{2}}{P_{\text {heater }}} \\
R &=\frac{120 \times 120}{1200}=12 \Omega
\end{aligned}
also, for the toaster
$$
R_{\text {loaster }}=\frac{120 \times 120}{600}=24 \Omega
$$
If both appliances are operated in parallel, then
$$
\begin{aligned}
&R_{c q}=\frac{R_{1} R_{2}}{R_{1}+R_{2}} \\
&R_{e q}=\frac{12 \times 24}{12+24} \\
&R_{c q}=8 \Omega
\end{aligned}
$$
and finally
Total current \(=\frac{V}{R}\)
$$
i=\frac{240}{8}=15 A
$$