The coefficient of linear expansion of aluminum is $23\times {10}^6{K}^{-1}$. If the volume of a pot made with aluminum at temperature $T_0$ is $V_{11}$, what will be the change in temperature resulting in a decrease of $0.20\mathrm{\%}$ in volume of the pot?

A. $-{87}^{\circ }C$
B. $+{487}^{\circ }C$
C. $+{428}^{\circ }C$
D. $-{29}^{\circ }C$  

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Correct Answer: D