Given parameters;
\(F=10 N\)
spring constant \(K=200 N / m\)
We require energy stored \(E=\) ?
correlating equation,nergy \(=1 / 2 k e^{2}\)
and by Hooke's law \(F =k e ; e=f l k\)
so that
\(\Rightarrow E=\frac{1}{2} K \cdot \frac{F^{2}}{K^{2}}=\frac{1}{2} \frac{F^{2}}{K}\)
\(E=\frac{1}{2} \times \frac{10^{2}}{200^{2}}=\frac{1}{2} \times \frac{100}{200}\)
\(E=0.25 J\).