Ice from \(-10^{\circ} C\) to water at \(90^{\circ} C\), the process involves three stages i.e
Stage 1
\(Q_{1}=\) heat required to change the ice at \(-10^{\circ} C\) to water at \(0^{\circ} C = m _{i c e} C _{\text {ice }} \times \Delta \theta\)
\(Q _{2}=\) heat required to change all the ice to water at \(0^{\circ} C =\)
\(Q_{3}=\) heat required to raise the temperature of water at \(0^{\circ} C\) to \(90^{\circ} C = m _{\text {water }} C _{\text {water }} \Delta \theta\)
Hence, specific latent heat of vapourisation is not required here.