Two positive point charge of \(12 \mu C\) andi \(\mu \mu C\) respectively are \(10 cm\) apart. The work done is bringing them \(4 cm\) closer \(T\) is \(\left( K =9 \times 10^{2} N ^{2} mc ^{2}\right)\)
A. \(600 J\) B. \(300 J\) C. \(6.8 J\) D. \(518 J\)
Correct Answer: D
Explanation
Work plontriblet Distancet \(0_{2}=8 \mu C , \quad r=10 cm d=6 cm\) \(F =\frac{9 \times 10^{6} \times 12 \times 10^{-6} \times 8 \times 10^{-6}}{(0.1)^{2}}=86.4 \mu \) Work done \(=86.4 \times 6\) =518.4 J
