A solid weighs \(0.040 N\) in air and \(0.024 N\) when fully immersed in a hapuid of density \(800 kgm\). Calculate the volume of the solid \(( g =10 ms 2)\)
A. \(2.0 \times 10^{-6} m ^{3}\) B. \(2.5 \times 10^{-6} m ^{3}\) C. \(3.0 \times 10^{-6} m ^{3}\) D. ( \(2.0 \times 10^{-8} m ^{-5}\)
Correct Answer: A
Explanation
Weight of liquid displaced \(=\) proust \begin{aligned} &=(0.040-.024) N \\ &=0.016 N =0.016 / 1 d =1.6 \times 10^{-3} kg \end{aligned} Volume of the object \(=\) Volume of liquid displaced \begin{aligned} &=\frac{\text { Mass of lquid }}{\text { density of liquid }}=\frac{1.6 \times 10^{-1} kg }{800 kgm ^{-2}} \\ &=2.0 \times 10^{6} m ^{3} \text {} \end{aligned}
