An electron of mass 9.1 x 10\(^{-31}\) kg moves with a speed of 2.0 x 10\(^6\) ms\(^{-1}\) round the nucleus of an atom in a Circular path of radius 6.1 x 10(^{11}\) m. Determine the angular speed of the electron.
A. 3.28 x 10\(^{16}\) rad s\(^{-1}\) B. 8.55 x 10\(^{3}\) rad s\(^{-1}\) C. 9.11 x 10\(^{13}\) rad s\(^{-1}\) D. 5.22 x 10\(^{15}\) rad s\(^{-1}\)
Correct Answer: A
Explanation
Angular speed of the electron (W) w = \(\frac{Velocity}{Radius} = \frac{V}{R}\) = \(\frac{2.0 \times 10^6}{6.1 \times 10^{11}}\) = 3.28 x 10\(^{16}\) rads\(^{-1}\)
