0.5kg of water at 10ºC is completely converted to ice at 0ºC by extracting (88000) of heat from it. If the specific heat capacity of water is 4200jkg Cº. Calculate the specific latent heat of fusion of ice.
Explanation
Heat involved (H) = 88,000J, Mass(M)= 0.5kg, specific heat capacity of water(C) = 4200JkgºC,
Specific latent heat of fusion(L) = ?, Temperature change(Δθ) = θ2 - θ1 = (10 - 0)° = 10°
H = MCΔθ + ML
or
H = M(CΔθ + L) --> = CΔθ + L
: L = - CΔθ = - 4200 10
L = 176,000 - 42000 = 134,000
L = 134,000 or 134kj/kg
