f\(_{0}\) = 40H\(_{3}\)
1st overtone = 2f\(_{0}\) = 80H\(_{3}\)
2nd overtone = 3f\(_{0}\) = 120H\(_{3}\)
3rd overtone = 4f\(_{0}\) = 160H\(_{3}\)
4th overtone = 5f\(_{0}\) = 200H\(_{3}\)
\(\therefore\) Number of overtones between 40H\(_{3}\) and 180H\(_{3}\) = 3