A solid weighs 4.8g in air, 2.8g in water and 3.2g in Kerosine. The ratio of density of the solid to that of the kerosine is
A. 2 B. \(\frac{3}{2}\) C. \(\frac{2}{3}\) D. 3
Correct Answer: D
Explanation
Relative density of solid \(\frac{\text{weight of solid}}{\text{weight of an equal volume of water}}\) = \(\frac{4.8}{4.8 - 2.8}\) = \(\frac{4.8}{2}\) = 2.4 Relative density of liquid = \(\frac{\text{Weight of liquid kerosine}}{\text{Weight of an equal volume of water}}\) = \(\frac{4.8 - 3.2}{4.8 - 2.8}\) = \(\frac{1.6}{2}\) = 0.8 = \(\frac{\text{Ratio of relative density of solid}}{\text{Relative density of Kerosine}}\) = \(\frac{\text{density of solid}}{\text{density of Kerosine}}\) = \(\frac{2.4}{0.8}\) = 3