(a) Define uniform acceleration. (b) Forces act on a car in motion. List the (i) horizontal forces and their directions; (ii) vertical forces and their directions (c) A car starts from rest and accelerate uniformly for 20s to attain a speed of 25 ms\(^{-1}\). It maintains this speed for 30s before decelerating uniformly to rest. The total time for the journey is 60s. (i) Sketch a velocity-tune graph for the motion. (ii) Use the graph to determine the (\(\alpha\)) total distance travelled by the car (\(\beta\)) deceleration of the car. The figure here illustrates force-extension graph for a stretched spiral spring. Determine the work done on the spring.

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(a) Define uniform acceleration.
(b) Forces act on a car in motion. List the
(i) horizontal forces and their directions;
(ii) vertical forces and their directions

(c) A car starts from rest and accelerate uniformly for 20s to attain a speed of 25 ms

^{- 1}

. It maintains this speed for 30s before decelerating uniformly to rest. The total time for the journey is 60s.
(i) Sketch a velocity-tune graph for the motion.
(ii) Use the graph to determine the (

α

) total distance travelled by the car (

β

) deceleration of the car.

The figure here illustrates force-extension graph for a stretched spiral spring. Determine the work done on the spring.

Explanation

(a) Uniform acceleration is the constant time rate of increase in velocity.
(b) (i) Horizontal Force;
Forward force - Thrust
backward force - Frictional force
(ii) Vertical Force
Upward force - Normal reaction.
Downward force - Weight of the car.

(c)

(ii) (

λ

) Total distance
= Area of trapezium OABC
=

\frac{1}{2}

[AB + OC] AD
=

\frac{1}{2}

[60+30] x 25
=1125m
(

β

) Deceleration = slope of BC
=

\frac{B E}{C E} = \frac{25}{10}

= 25m/s

^{2}

(d) Work done =

\frac{1}{2}

Fe
=

\frac{1}{2}

x 12 x

\frac{0.5}{100}

J
= 0.03J

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(a) Define uniform acceleration. (b) Forces act on a car in motion. List the (i) ...

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