A circuit is set up as shown in the diagram above. When the key is closed, the ammeter reading will be
A. 6A B. 4A C. 2A D. 1A
Correct Answer: C
Explanation
The resistors are connected both in parallel and series. To calculate the total resistance, we have: For the parallel connection: \(\frac{1}{R} = \frac{1}{1} + \frac{1}{1}\) \(\frac{1}{R} = 2 \implies R = 0.5\Omega\) For the series connection: \(R_{total} = (1 + 0.5)\Omega = 1.5\Omega\) Recall, \(V=IR\) \(3 = 1.5I \implies I = \frac{3}{1.5} =2A\)
