The horizontal component of the initial speed of a particle projected at 30° to the horizontal is 50 ms\(^{-1}\). If the acceleration cf free fall due to gravity is 10ms\(^{-2}\), determine its: (a) initial speed; (b) speed at maximum height reached.
Explanation
(a) If initial velocity = U Then horizontal component \(U_x = Ucos\theta\) Ucos\(\theta\) = 50 U = \(\frac{50}{cos \theta} = \frac{50}{cos 30^o}\) = 57.7m/s
(b) But at maximum height V = O V\(_y\) = O V\(_x\) = U\(_x\) = 50m/s
