An object is placed 10cm from a converging lens of foal length 15cm. Calculate the magnification of the image formed
A. 3.0 B. 1.5 C. 0.6 D. 0.3
Correct Answer: A
Explanation
\(\frac{1}{f} = \frac{1}{v} + \frac{1}{u}\) \(\frac{1}{v} = \frac{1}{f} - \frac{1}{u}\) \(\frac{1}{15} - \frac{1}{10} = \frac{2 - 3}{30}\) \(\frac{1}{v} = \frac{-1}{30}\) v = - 30 cm but m = \(\frac{v}{u} = \frac{30}{10} = 3\) Note that the negative sign only shows the placement of the image. It has no effect on the magnification basically.