A piece of copper of mass 20g at a temperature of 110°C was dropped into a mixture of ice and water at 0°C. If the final steady temperature of the mixture is 0°C . Calculate the amount of ice that melted [Specific heat capacity of copper = 0.4 Jg\(^{-1}\)K\(^{-1}\), specific latent heat of fusion of ice = 330Jg\(^{-1}\)]
A. 0.37g B. 0.60g C. 2.40g D. 2.70g
Correct Answer: D
Explanation
Mice = \(\frac{MC}{\theta}\) = \(\frac{20 \times 0.4 \times 110}{330} Heat lost by copper = Heat gained by ice m\(_{copper}\) c \(\theta\) = m\(_{ice}\) L 20 x 0.4 x (110 - 0) = m\(_{ice}\) x 330 m\(_{ice}\) = \(\frac{20 \times 0.4 \times 110}{330}\) = \(\frac{8}{3}\) = 2.67 g = 2.70g (to 1 d.p)
