(a) The sum of the clockwise moments about a point = the sum of the anticlockwise moments about the same point
(b)(i)
Take a moment about the fulcrum F
60 x 24 = m x 18
m = \(\frac{60 \times 24}{18}\)
= 80g
(ii)
Take a momen about F, 60 x (\(x\) - 13) = 80 x (48 - \(x\))
3(\(x\) - 13) = 4(48 - \(x\))
3\(x\) - 39 = 192 - 4\(x\)
7\(x\) = 231
\(x = \frac{231}{7}\) = 33cm
(c)(i)
(ii)
(i) Minimum effort E = F + mgsin\(\theta\) = 1000 + 700 sin \(\theta\) = 1350N
(ii) V.R = \(\frac{1}{sin \theta} = \frac{1}{sin 30}\) = 2
(ii) M.A = \(\frac{L}{E} = \frac{700}{1350}\) = 0.52
