(a) Uniform acceleration occurs when the change in velocity per unit time is constant. The S.I. unit is ms\(^{-2}\).
\(a = \frac{v - u}{t}\); a - uniform acceleration, v - final velocity, u - initial velocity, t - time.
Graphically,

acceleration is the same acceleration at x is different every point from that at Y.
Note - acceleration is given by slope in both graphs.
(b)
(i) Maximum speed = 240 m/s.
(ii) \(a = \frac{v - u}{t} = \frac{0 - 200}{20} = -10 ms^{-2}\)
(iii) Area of I = \(\frac{1}{2} \times 30 \times 240 = 3600m\)
Area of II = \(20 \times 200 = 4000m\)
Area of III = \(\frac{1}{2} \times 20 \times 40 = 400m\)
Total distance in the first 50s : \(3600m + 4000m + 400m = 8000m\)
(iv) Average speed during the first 50s = \(\frac{8000m}{50s} = 160 ms^{-1}\)