Two capacitors C₁ and C₂ are connected as shown in the diagram. The capacitance C₂ is twice C₁ when the key is opened the energy stored up in C₁ is W. If the key is later closed and the system is allowed to attain electrical equilibrium, the total energy stored in the system will be

A. \(\frac{1}{2}\)W
B. \(\frac{2}{3}\)W
C. W
D. 2w
E. 3W  

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Correct Answer: E