The image of an object is located 6cm behind a convex mirror. If it's magnification is 0.6, calculate the focal length of the mirror
A. 3.75cm B. 6.70cm C. 10.00cm D. 15.00cm
Correct Answer:
Explanation
V = 6cm  M = 6cm  Recall m = U = \(\frac{V}{U}\)  U = \(frac{V}{M}\)  =U = \(\frac{6}{0.6}\)  U = 10  \(\frac{1}{U}\) + \(\frac{1}{V}\) = \(\frac{1}{F}\)  \(\frac{1}{10}\) + \(\frac{1}{6}\) = \(\frac{1}{F}\)  6 + \(\frac{10}{60}\) \(\frac{16}{60}\) = \(\frac{1}{F}\)  F = \(\frac{60}{16}\) = 3.75cm
