A solid cube of side 50cm and mass 75kg floats in a liquid with \(\frac{1}{3}\) of its height above the liquid surface. The relative density of the liquid is?
A. 0.33 B. 0.50 C. 0.67 D. 0.90
Correct Answer: D
Explanation
Volume of liquid displaced  = \(\frac{2}{3}\)(0.5)\(^3\)  Mass of liquid displaced = mass of floating cube = 75kg  Density of liquid = \(\frac{mass}{volume}\)  = \(\frac{75}{(\frac{7}{3(0.5)})}\) × 3  = 0.9 × 103kgm\(^{-3}\)  R.D of liquid = \(\frac{(0.9 )}{(1.0)}\) × 103  = 0.9
