Calculate the upthrust on an object of volume 50cm3 which is immersed in liquid of density 103kgm-3 [g = 10ms-2]
A. 0.8N B. 2.5N C. 0.5N D. 1.0N
Correct Answer: C
Explanation
Upthrust = change in weight density = \(\frac{\text{mass}}{\text{volume}}\) Mass of liquid displaced = Density of Liquid × Volume; = \(10^{3} \times 50 \times 10^{−6}m^{3}\) = 0.05kg (Note that the volume of \(50cm^{3}\) was converted to \(m^{3}\) by multiplying by \(10^{6}\)) i.e \(50cm^{3} = 50 \times 10^{−6}m^{3}\) Since mass displaced = 0.05kg Upthrust = mg = 0.05 × 10 = 0.5N