Calculate the mass of ice that would melt when 2kg of copper is quickly transferred from boiling water to a block of ice without heat loss; Specific heat capacity of copper = 400JKg-1K-1 Latent heat of fusion of ice = 3.3 x 105JKg-1
A. 8/33kg B. 33/80kg C. 80/33kg D. 33/8kg
Correct Answer: A
Explanation
Heat given off by the copper = MCt = 2 x 400 x (100 - 0) Heat absorbed by the ice = ML = M x 3.3 x 105 Heat lost = Heat gained ∴ M x 3.3 x 105 = 2 x 400 x 100 ∴ M = (2 x 400 x 100)/3.3 x 105 = 8/33Kg
