Two balls X and Y weighing 5 g and 50 kg respectively were throne up vertically at the same time with a velocity of 100 ms1 .How will their positions be one second later?
A. X and Y will be 500 m from each other B. Y will be 500 m ahead of X C. X will be 500 m ahead of Y D. X and Y both be 500 m from the poin of throw
Correct Answer: D
Explanation
v2 = U2 - 2G s 0 = 1002 - 2 x 10 x s = 10000 - 20s s = (10000)/20 = 500m Which is independent of mass.the two bodies where acted upon by the same retarding force of gravity which is independent of mass of the body; therefore both will be 500 m from the point of throw.
