A piece of iron weights 250 N in air and 200 N in a liquid of density 1000 kgm-3. the volume of the iron is?
A. 5.0 x 10-2 ms-2 B. 4.5 x 10--2 ms-3 C. 2.5 x 10-2 ms-8 D. 2.0 x 10-2 ms-3
Correct Answer: C
Explanation
With in the air = 250N wt. in the liquid = 200N loss in wt. in the liquid = 250 - 200 = 50N ∴ Wt. the liquid of equal vol. of the iron = 50N ∴If the density of the liquid is 1000 lgm-3 then the volume of the liquid = (N)/D = V = (25kg)/1000 =0.025m3 = 2.5 x 10-2 m8.
