Quantity of heat required to raise the temperature of the ice cube from $-{10}^{o}C$ to $0^{o}C$
⇒H=mc►ø = 0.02 × 2100 × 0 -(-10)

⇒ H = 0.02 × 2100 × (0 + 10) = 0.02 × 2100 × 10

⇒ H = 420 J

quantity of heat required to melt ice at $0^{o}C$

⇒ H = mL = 0.02 × 3.34 × ${10}^5$

⇒H=6680 j

Quantity of heat required to raise the temperature of the melted ice cube (water) from $0^{o}C$ to $-{10}^{o}C$

⇒H=mc►ø = 0.02 × 4200 × (10-0)

⇒H = 0.02 × 4200 × 10

⇒H = 840j

;420 + 6680 + 840 = 7940 j