A ray of light is incident on an equilateral triangular glass prism of refractive index 3/2, Calculate the angle through which the ray is minimally deviated in the prism
A. 30.0\(^{\circ} \) B. 37.2\(^{\circ} \) C. 42.0\(^{\circ} \) D. 48.6\(^{\circ} \)
Correct Answer: B
Explanation
For the equilateral glass prism A = 600 \( \frac{3}{2} \text{Sin} \frac{\left( \frac{Dm + 60}{2}\right)}{\left(\frac{60}{2}\right)}= \frac{\left( \text{ Sin }\frac{Dm + 60}{2} \right)}{0.5} \\ \implies Dm = 37.2^{\circ} \)
