An electron of charge 1.6 x 10-19C is accelerated between two metal plates. If the kinetics energy of the electron is 4.8 x 10-17J, the potential difference between the plate is
A. 30V B. 40V C. 300V D. 400V
Correct Answer: C
Explanation
In general, if a charged particle is accelerated between two metal plates/a region by potential difference V volts, the work done on the charge, given by the product of the charge and the potential difference, is equal to the kinetic energy of the charge Thus eV = K.E 1.6 x 10-19 x V = 4.8 x 10-17
