A coin place below a rectangular glass block of thickness 9cm and refractive index 1.5 is viewed vertically above the block. The apparent displacement of the coin is
A. 3 cm B. 5 cm C. 6 cm D. 8 cm
Correct Answer: A
Explanation
Real depth = thickness of the glass block = 9cm. Refractive index of the glass material = 1.5 But Refractive index = Real depth/Apparent depth => 1.5 = 9/Apparent depth therefore Apparent depth = 9/1.5 = 6cm. therefore Apparent displacement of the Coin = 9.6 = 3cm
