Three electric cells each of e.m.f 1.5V and internal resistance of 1.0\(\Omega\) are connected in parallel across an external resistance of \(\frac{2}{3}\)\(\Omega\). Calculate the value of the current in the resistor
A. 0.5 A B. 0.9A C. 1.5A D. 4.5A
Correct Answer: C
Explanation
E.m.f = 1.5 r = \(\frac{1 \times\ 1 \times 1}{(1 \times\ 1) + (1 \times\ 1) + (1 \times\ 1)}\) r = \(\frac{1}{3}\)\(\Omega\) I = \(\frac{E.m.f}{r + R}\) I = \(\frac{1.5}{\frac{1}{3}\ + \frac{2}{3}}\) I = 1.5A
