The hatch door of a submarine has an area of 0.5m2. The specific gravity of sea water is 1.03. Assume that g = 10ms-1,and neglect the atmospheric pressure. The force exerted by the sea water on the hatch door at a depth of 200m is
A. 1.03 x 105N B. 1.03 x 104Nm-2 C. 1.06 x 105Nm-2 D. 2.06 x 106N E. 1.03 x 103N
Correct Answer: E
Explanation
Pressure in liquid = e x h x g Pressure in solid = \(\frac{force}{area}\) \(\frac{force}{area}\) = e x h x g force = 0.5 x 10 x 200 x 1.03 = 1030N
