A solid weighs 4.8g in air, 2.8g in water and 3.2g in kerosine. The ratio of density of the solid to that of the kerosine is
A. 12 B. 3 C. 2 D. \(\frac{3}{2}\) E. \(\frac{5}{4}\)
Correct Answer: B
Explanation
Relative density of solid = \(\frac{\text{weight of solid}}{\text{weight of an equal volume of water}}\) \(\frac{4.8}{4.8 -3.2}\) = \(\frac{4.8}{2}\) = 2.4 Ratio of density of liquid = \(\frac{\text{weight of liquid kerosine}}{\text{weight of an equal volume of water}}\) = \(\frac{4.8 - 3.2}{4.8 - 2.8}\) = \(\frac{1.6}{2}\) = 0.8 = \(\frac{\text{density of solid}}{\text{density of kerosine}}\) = \(\frac{2.4}{0.8}\) = 3
