Let the no be \(a \& b\)
\begin{aligned}
&a-b=10 \text {-. }(1) \\
&a \times b=39 \ldots(2) \\
&\text { from } a=39 / b \\
&\frac{39}{b}-b=10 \\
&39-b 2=10 b \\
&h 2+10 b-39=0 . \\
&h(b+13)-3(b+13) \\
&h=3 \text { or } b=-13 . \\
&\text { When } b=3 \\
&a-3=10, a=13 \\
&\text { when } b=-13 \\
&a-(-13)=10 . a=-3 \\
&\text { Ans }=-3 \text { and }-13 \text { or } 13 \text { and } 3
\end{aligned}