In the figure \(A B\) and \(A D\) are tangents to the circle. If \(B C S=55^{\circ}\) and \(BDC =48^{\circ}\). find \(B A D\). [image]
A. \(55^{\circ}\) B. \(70^{\circ}\) C. \(77^{\circ}\) D. \(84^{\circ}\)
Correct Answer: B
Explanation
Considering the given shape, \(ABD = BCD \quad\) (angle in alternate segment) \(ADB = BCD =55^{\circ} \quad\) (angle in alternate segment) \(ABD + ADB + BA D =180^{\circ}\) (sum of angles in a \(\Delta\) ) \(55^{\circ}+55^{\circ}+ BA A =180^{\circ}\) \(BAD =180^{\circ}-110^{\circ}=70^{\circ}\)