\(\frac{1}{\sqrt{3}} y-x=0\)
rearranging the equation. we have \(x=\frac{y}{\sqrt{3}}\) or \(y=\sqrt{3} x\)
we compare this with the general equation of a
straight line i.e. \(y=m x+c\)
where \(m\) is the slope, \(m=\sqrt{3}\)
but slope \(m=\tan \theta\)
\begin{aligned}
\tan \theta &=\sqrt{3} \\
\theta &=\tan ^{-1}(\sqrt{3})=60^{\circ}
\end{aligned}
\(\therefore\) Angle made with the positive \(y\) - axis is \(90^{\circ}-60^{\circ}=30^{\circ}\)