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\(\begin{array}{c|c} No 0 1 2 3 4 5 \\ \hline Frequency 1 4 3 8 2 5 ...
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Classroom
Mathematics Classroom
Jamb
Topics
Jamb 2011
STATISTICS
Measures Of Location
Median
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\(\begin{array}{c|c} No & 0 & 1 & 2 & 3 & 4 & 5 \\ \hline Frequency & 1 & 4 & 3 & 8 & 2 & 5 \end{array}\). From the table above, find the median and range of the data respectively.
A.
(8,5)
B.
(3, 5)
C.
(5 , 8)
D.
(5 , 3)
Show Answer
Show Explanation
Correct Answer: B
Explanation
Median = \(\frac{\sum fx}{\sum f}\)
\(\begin{array}{c|c}
No & 0 & 1 & 2 & 3 & 4 & 5 \\ F & 1 & 4 & 3 & 8 & 2 & 5 \\ fx & 0 & 4 & 6 & 24 & 8 & 25 \end{array}\)
\(\sum fx\) = 0 + 4 + 6 + 24 + 8 + 25 = 67
\(\sum f\) = 23
Median = \(\frac{\sum fx}{\sum f}\) = \(\frac{67}{23}\) = 2.913
= \(\approx\) 3
Range = 5 - 0 = 5
(3, 5)
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