\(Surface area (A) = 4\pi r^{2} = 616m^{2}\)
solving, we have
\(r = 7m\)
\(Volume = \frac{4}{3}\pi r^{3}\)
\(Volume = \frac{4\times 3.142 \times 7^{3}}{3}\)
\(Volume = \frac{4310.824}{3}\)
= \(1436.941m^{3} \approxeq 1400m^{3}(2 sig. fig)\)