Equation: x\(^3\) - 2x\(^2\) - 5x + 6 = 0.
First, bring out a\(_n\) which is the coefficient of x\(^3\) = 1.
Then, a\(_0\) which is the coefficient void of x = 6.
The factors of a\(_n\) = 1; The factors of a\(_0\) = 1, 2, 3 and 6.
The numbers to test for the roots are \(\pm (\frac{a_0}{a_n})\).
= \(\pm (1, 2, 3, 6)\).
Test for +1: 1\(^3\) - 2(1\(^2\)) - 5(1) + 6 = 1 - 2 - 5 + 6 = 0.
Therefore x = 1 is a root of the equation.
Using long division method, \(\frac{x^3 - 2x^2 - 5x + 6}{x - 1}\) = x\(^2\) - x - 6.
x\(^2\) - x - 6 = (x - 3)(x + 2).
x = -2, 3.
\(\therefore\) The roots of the equation = 1, -2 and 3.