In the figure, PQST is a parallelogram and TSR is a straight line. If the area of \(\bigtriangleup\)QRS is 20cm2, find the area of the trapezium PQRT.
A. 35cm2 B. 65cm2 C. 70cm2 D. 140cm2
Correct Answer: C
Explanation
A\(\bigtriangleup\) = \(\frac{1}{2}\) x 8 x h = 20 = \(\frac{1}{2}\) x 8 x h = 4h h = \(\frac{20}{4}\) = 5cm A\(\bigtriangleup\)(PQTS) = L x H A\(\bigtriangleup\)PQRT = A\(\bigtriangleup\)QSR + A\(\bigtriangleup\)PQTS 20 + 50 = 70cm2 ALTERNATIVE METHOD A\(\bigtriangleup\)PQRT = \(\frac{1}{2}\) x 5 x 28 = 70cm2
