Find the range of values of x which satisfies the inequality 12x² < x + 1

A. -\(\frac{1}{4}\) < x < \(\frac{1}{3}\)  
B. \(\frac{1}{4}\) < x < -\(\frac{1}{3}\)
C. -\(\frac{1}{3}\) < x < \(\frac{1}{4}\)
D. -\(\frac{1}{4}\) < x < - \(\frac{1}{3}\)

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Correct Answer: A