sin \(\theta\) = cos \(\theta\) 0 \(\leq\) \(\theta\) \(\leq\) 360o
The acute angle where sin \(\theta\) = cos \(\theta\) = 45o
But at the third Quadrant Cos \(\theta\) = -ve; sin \(\theta\) = -ve.
at the 3rd quadrant, value with respect to Q is
(180 + Q) where Q = acute angle
(180 + 45) = 225°
The two solution are 45°, 225°